Find the compound interest on Rs 2000 at 15% per annum for 2 years 4 months, compounded annually

Compound Interest: The future value (FV) of an investment of present value (PV) dollars earning interest at an annual rate of r compounded m times per year for a period of t years is:

FV = PV(1 + r/m)mtor

FV = PV(1 + i)n

where i = r/m is the interest per compounding period and n = mt is the number of compounding periods.

One may solve for the present value PV to obtain:

PV = FV/(1 + r/m)mt

Numerical Example: For 4-year investment of $20,000 earning 8.5% per year, with interest re-invested each month, the future value is

FV = PV(1 + r/m)mt   = 20,000(1 + 0.085/12)(12)(4)   = $28,065.30

Notice that the interest earned is $28,065.30 - $20,000 = $8,065.30 -- considerably more than the corresponding simple interest.

Effective Interest Rate: If money is invested at an annual rate r, compounded m times per year, the effective interest rate is:

reff = (1 + r/m)m - 1.

This is the interest rate that would give the same yield if compounded only once per year. In this context r is also called the nominal rate, and is often denoted as rnom.

Numerical Example: A CD paying 9.8% compounded monthly has a nominal rate of rnom = 0.098, and an effective rate of:

r eff =(1 + rnom /m)m   =   (1 + 0.098/12)12 - 1   =  0.1025.

Thus, we get an effective interest rate of 10.25%, since the compounding makes the CD paying 9.8% compounded monthly really pay 10.25% interest over the course of the year.

Mortgage Payments Components: Let where P = principal, r = interest rate per period, n = number of periods, k = number of payments, R = monthly payment, and D = debt balance after K payments, then

R = P r / [1 - (1 + r)-n]

and

D = P (1 + r)k - R [(1 + r)k - 1)/r]

Accelerating Mortgage Payments Components: Suppose one decides to pay more than the monthly payment, the question is how many months will it take until the mortgage is paid off? The answer is, the rounded-up, where:

n = log[x / (x � P r)] / log (1 + r)

where Log is the logarithm in any base, say 10, or e.

Future Value (FV) of an Annuity Components: Ler where R = payment, r = rate of interest, and n = number of payments, then

FV = [ R(1 + r)n - 1 ] / r

Future Value for an Increasing Annuity: It is an increasing annuity is an investment that is earning interest, and into which regular payments of a fixed amount are made. Suppose one makes a payment of R at the end of each compounding period into an investment with a present value of PV, paying interest at an annual rate of r compounded m times per year, then the future value after t years will be

FV = PV(1 + i)n + [ R ( (1 + i)n - 1 ) ] / i where i = r/m is the interest paid each period and n = m t is the total number of periods.

Numerical Example: You deposit $100 per month into an account that now contains $5,000 and earns 5% interest per year compounded monthly. After 10 years, the amount of money in the account is:

FV = PV(1 + i)n + [ R(1 + i)n - 1 ] / i =
5,000(1+0.05/12)120 + [100(1+0.05/12)120 - 1 ] / (0.05/12) = $23,763.28

Value of a Bond:

V is the sum of the value of the dividends and the final payment.

You may like to perform some sensitivity analysis for the "what-if" scenarios by entering different numerical value(s), to make your "good" strategic decision.

Replace the existing numerical example, with your own case-information, and then click one the Calculate.

Time = 2 years 4 months = 2(4/12) years = 2(1/3) years. 

Amount = Rs'. [8000 X (1+(15/100))2 X (1+((1/3)*15)/100)] 

=Rs. [8000 * (23/20) * (23/20) * (21/20)] 

= Rs. 11109. . 

  C.I. = Rs. (11109 - 8000) = Rs. 3109.

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15 Questions 15 Marks 15 Mins

Given:

Principal amount = Rs. 2000

Rate of interest = 3% pa

Time = 2 years

Concept used:

Compound interest, CI = P(1 + R/100)n - P

where

P = Principal amount

R = Rate of interest per year

N = Time in years

Calculation:

So, the compound interest 

⇒ 2000 (1 + 3/100)2 - 2000

⇒ 121.80

∴ The compound interest on Rs 2,000 for 2 years at 3% p.a. is Rs. 121.80.

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Let's discuss the concepts related to Interest and Compound Interest. Explore more from Quantitative Aptitude here. Learn now!

What is the compound interest on Rs 8000 at 15% per annum for 2 years 4 months compounded annually?

Compound interest = ₹ 11109 - ₹ 8000 = ₹ 3109. Q. Find compound interest on Rs. 8000 at 15% per annum for 2 years 4 months, compounded annually.

What is the simple interest on Rs 8000 at 15% per annum for 2 years?

11109 - 8000 = Rs. 3109.

What will be the compound interest on 2000 for 2 years?

∴ The compound interest on Rs 2,000 for 2 years at 3% p.a. is Rs. 121.80.

What is the compound interest on rupees 20000 at 10% for 2 years?

Where P is principal, R is rate of interest and T is time. ∴ The compound interest for 2 years is Rs. 2464.